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PHP

Copy part of an image


imagecopy

(PHP 4, PHP 5)

imagecopyCopy part of an image

Description

bool imagecopy ( resource $dst_im , resource $src_im , int $dst_x , int $dst_y , int $src_x , int $src_y , int $src_w , int $src_h )

Copy a part of src_im onto dst_im starting at the x,y coordinates src_x, src_y with a width of src_w and a height of src_h. The portion defined will be copied onto the x,y coordinates, dst_x and dst_y.

Parameters

dst_im

Destination image link resource.

src_im

Source image link resource.

dst_x

x-coordinate of destination point.

dst_y

y-coordinate of destination point.

src_x

x-coordinate of source point.

src_y

y-coordinate of source point.

src_w

Source width.

src_h

Source height.

Return Values

Returns TRUE on success or FALSE on failure.

Examples

Example #1 Cropping the PHP.net logo

<?php
// Create image instances
$src imagecreatefromgif('php.gif');
$dest imagecreatetruecolor(8040);

// Copy
imagecopy($dest$src0020138040);

// Output and free from memory
header('Content-Type: image/gif');
imagegif($dest);

imagedestroy($dest);
imagedestroy($src);
?>

The above example will output something similar to:

output of example : cropping the php.net logo



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